X^2+36x=88

Solution for X^2+36x=88 equation:

X^2+36X=88

We move all terms to the left:

X^2+36X-(88)=0

a = 1; b = 36; c = -88;
Δ = b2-4ac
Δ = 362-4·1·(-88)
Δ = 1648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1648}=\sqrt{16*103}=\sqrt{16}*\sqrt{103}=4\sqrt{103}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{103}}{2*1}=\frac{-36-4\sqrt{103}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{103}}{2*1}=\frac{-36+4\sqrt{103}}{2}
$